Aplikasi Pencari Invers Matriks Ordo 3x3 Dengan Metode Adjoin Mengguanakan Python3

Mencari invers matriks dengan ordo 3x3 ini bagi beberapa orang dianggap susah dan rumit. Dikarenakan untuk mencari invers ini kita bisa melalui dua metode yaitu metode adjoin dan metode OBE (Operasi Baris Elementer). Kedua metode ini memiliki step by step yang sangat diperhatikan.

Namun melalui aplikasi ini diharapkan user dapat memahami proses alur pencarian invers matriks dengan orde 3x3. Aplikasi ini menggunakan metode adjoin. Disini saya menggunakan bahasa pemrograman Python versi 3. Berikut ini adalah source codenya :

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import os

a=1
while a==1:
 print("=====Aplikasi Pencari Invers Matriks=====")
 
 a=int(input("Masukkan Nilai A = "))
 b=int(input("Masukkan Nilai B = "))
 c=int(input("Masukkan Nilai C = "))
 d=int(input("Masukkan Nilai D = "))
 e=int(input("Masukkan Nilai E = "))
 f=int(input("Masukkan Nilai F = "))
 g=int(input("Masukkan Nilai G = "))
 h=int(input("Masukkan Nilai H = "))
 i=int(input("Masukkan Nilai I = "))

#Determinan
 detA=(a*e*i)+(b*f*g)+(c*d*h)-(g*e*c)-(h*f*a)-(i*d*b)
 print("\n=====MATRIKS A=====")
 print("|`",a," ",b," ",c,"`|")
 print("| ",d," ",e," ",f," |  ===> DetA = ",detA)
 print("|_",g," ",h," ",i,"_|")
 print("===============================")

#Adjoin
 a11=(e*i)-(h*f)
 a12=(d*i)-(g*f)
 a13=(d*h)-(g*e)
 a21=(b*i)-(h*c)
 a22=(a*i)-(g*c)
 a23=(a*h)-(g*b)
 a31=(b*f)-(e*c)
 a32=(a*f)-(d*c)
 a33=(a*e)-(d*b)
 print('=====ADJOIN======')
 print("A11 = (+)| ",e,"",f," |=",a11," A12 = (-)| ",d,"",f," |=",a12," A13 = (+)| ",d,"",e," |=",a13)
 print("         | ",h,"",i," |              | ",g,"",i," |              | ",g,"",h," |")

 print("\nA21 = (-)| ",b,"",c," |=",a21," A22 = (+)| ",a,"",c," |=",a22," A23 = (-)| ",a,"",b," |=",a23)
 print("         | ",h,"",i," |              | ",g,"",i," |              | ",g,"",h," |")

 print("\nA31 = (+)| ",b,"",c," |=",a31," A32 = (-)| ",a,"",c," |=",a32," A33 = (+)| ",a,"",b," |=",a33)
 print("         | ",e,"",f," |               | ",d,"",f," |              | ",d,"",e," |")

#printAdjoin
 print("==============================================================================")
 print("Adj = | ",a11*(1),"",a12*(-1),"",a13*(1)," |")
 print("      | ",a21*(-1),"",a22*(1),"",a23*(-1)," |")
 print("      | ",a31*(1),"",a32*(-1),"",a33*(1)," |")
 print("")
 print("Adjoin di Transpose menjadi = ")
 print("A Traspose = | ",a11*(1),'',a21*(-1),'',a31*(1),' |')
 print('             | ',a12*(-1),'',a22*(1),'',a32*(-1),' |')
 print('             | ',a13*(1),'',a23*(-1),'',a33*(1),' |')
 print("==============================================================================")

#invers
 ina11=(1/detA*(a11*(1)))
 ina12=(1/detA*(a12*(-1)))
 ina13=(1/detA*(a13*(1)))
 ina21=(1/detA*(a21*(-1)))
 ina22=(1/detA*(a22*(1)))
 ina23=(1/detA*(a23*(-1)))
 ina31=(1/detA*(a31*(1)))
 ina32=(1/detA*(a32*(-1)))
 ina33=(1/detA*(a33*(1)))

 print("\nA-1 = 1/Det A x Adj A")
 print('    = 1/',detA,"| ",a11,'',a21,'',a31," |")
 print('            | ',a12,'',a22,'',a32,' |')
 print('            | ',a13,'',a23,'',a33,' |')

 print('\n    = | ',ina11,'',ina21,'',ina31,' |')
 print('      | ',ina12,'',ina22,'',ina32,' |')
 print('      | ',ina13,'',ina23,'',ina33,' |')

 input("\nPress Enter to Continue!")
 os.system('cls')

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Link source code ==> Google Drive

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